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fix typo
Signed-off-by: szdytom <szdytom@qq.com>
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@ -387,7 +387,7 @@
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$ v = a_(k, 1) u_1 + dots.c + a_(k, n) u_n $
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#tab 且 $a_(k, m + k) = 0$。现在,对于任意 $j in {2, dots, n - m}$,我们将 $v$ 在 $W_1$ 和 $W_q$ 中线性组合的表达式相减,得到
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#tab 且 $a_(k, m + k) = 0$。现在,对于任意 $j in {2, dots, n - m}$,我们将 $v$ 在 $W_1$ 和 $W_j$ 中线性组合的表达式相减,得到
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$ 0 = (a_(1, 1) - a_(j, 1)) u_1 + dots.c + (a_(1, n) - a_(j, n)) u_n $
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